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+---
+title: "Calculating relative average subdirectory filesizes"
+date: 2020-08-21T12:37:00
+tags: [ "Guides", "Snippets", "Software", "Windows" ]
+---
+
+During these _unprecedented times_ I've been watching a fair amount of movies and TV shows, and deleting once done, as you do. As a bit of a interesting insight and guiding hand I've been using the excellent [ncdu](https://dev.yorhel.nl/ncdu) and [rclone's ...clone ](https://rclone.org/commands/rclone_ncdu/) which both work excellently for when 1 folder equates to 1 _media_. With TV shows however this is complicated somewhat. In steps calculating average filesizes in a directory so you can sort them revealing the most notorious offenders.
+
+I had a quick look online but couldn't find anything that really did what I wanted so I wrote it myself in an extremely verbose fashion. Eventually I slimmed it down to the following function:
+```
+for i in *; do s=$(du -s "$i" | awk '{print $1}') && c=$(find "$i" -type f -size +1M | wc -l) && echo "$((s / c)) $c $s $i"; done | sort -nr
+```
+
+What this does is:
+- Loops every item in the folder using `for`
+- Calculates the size `$s` using `du`
+- Counts the items in the folder `$c` using `find` ignoring small files, like subtitles
+- Divides the two to get the average
+- Prints the list, then reverse sorts it
+
+Giving you your results. Ta~da!
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